The Ed-Scale defines the perfect temperature of an iced tea to be 5.0\'E and the

Question

The Ed-Scale defines the perfect temperature of an iced tea to be 5.0'E and the boiling point of antifreeze to be 100°E. If on the Fahrenheit scale these occur at 38 F and 360°F, respectively, then write an equation that converts from Fahrenheit to Eds. Use this equation to find the freezing point of water in Eds. 1. a. 3.230 E b. 2.658°E d. 3.18FEHep d. 3.390 E e. 3.180 E 3.032"E c. 2.535"E SYSG ie doughnut. To burn-it-off, he decides to climb the steps of a tall building. How high (in m) would he have to climb to expend an equivalent amount of work? a. 707.0m b. 859.4 m c. 1044 m d. 714.8m e. 703.1 m f. 854.3m d 705.mHelp Suppose 2.50 kg of 32 C water is mixed with 9.30 kg of 65 'C water. If no heat is lost in this system, what is the final temperature of the water? 13. 4636 b. 47.06 C c. 58.01c d. 69.98 c e. 54.30 f. 63.90°C a. 46.36"C c. 58.01 ISPWN A perfect fluid flows through a pipe with varying radius. If at one cross section with radius 20 cm the fluid is flowing at 5.0 m/s, then what is the speed at a cross section with radius 4.0 cm? 7. a. 125.0 m/s b. 125.5 m/s c. 115.2 m/s d. 121.4 m/s e. 151.5 m/s f. 115.8 m/s

Explanation / Answer

4) 160 kilo calories = 669.44 joules

energy = work done = mgh

=> 669.4 = 80*9.8*h

=> h = 854.3 m

13)

m1*s*(Tf - T1) = m2*(T2 - Tf)

2.5*( Tf - 32) = 9.3*(65 - Tf )

11.8*Tf = 684.5

Tf = 58.0084

option (c)

7)

from the law of continuity

A1 * V1 = A2 * V2

Pi*(202)* 5 = Pi*42 * V2

V2 = 125 m/s

So option (a)

You are not supposed to ask more than one question at a time. anyhow i have answered three questions

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