Hello, please solve this problem for me. Was not covered in class. Thank you The

Question

Hello, please solve this problem for me. Was not covered in class. Thank you

The polar equation of planetary orbit is r = a( 1 - e^2) / (1 - e cos Theta), where e is the eccentricity and 2a is the length of the major axis (see figure). The minimum distance (perihelion) from the sun to the planet is given by r = a(1 - e) and the maximum distance (aphelion) is given by r = a(1 + e). Find the polar equation of the planet's orbit and the perihelion and aphelion. (Round all numerical values to four decimal places.) Venus a 1.0821 times 10^8 kilometers, e 0.0068 the polar equation of the planet's orbit (Round your answers to four decimal places.) r = times 10^8/ 1 -( )cos Theta the perihelion and aphelion (Round your answers to four decimal places.) perihelion times 10^8 km aphelion times 10^8 km

Explanation / Answer

a)

r = a*(1 - e^2)/( 1 - e*cos(theta))

= 1.0821*10^8*(1 - 0.0068^2)/(1 - 0.0068*cos(theta))

= 1.0820*10^8/(1 - 0.0068*cos(theta))

b)

perihelion = a*(1 - e)

= 1.0821*10^8*(1 - 0.0068)

= 1.0747*10^8 km

aphelion = a*(1 + e)

= 1.0821*10^8*(1 + 0.0068)

= 1.0895*10^8 km

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.