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a diagram would be very helpful When a star (assume it is a sphere) that is much

ID: 1482612 • Letter: A

Question

a diagram would be very helpful

When a star (assume it is a sphere) that is much more massive than our sun dies, it produces a supernova, a tremendous explosion in which the core of the star collapses under its own gravity. This process releases an enormous amount of energy in a few moments, and leaves behind a bizarre object called a neutron star, which is made entirely of neutrons and has an incredibly high density because it is only about 10 km in radius. If the star is initially rotating at 9 rev/day and its core has the same mass as our sun (2 Times 10^30 kg), find the rotation rate of the neutron star. (The initial radius of the star is assumed to be the radius of the Earth = 6370 km).

Explanation / Answer

Angular momentum is conserved.

I11 = I22

=> (2MR12/5)1 = (2MR22/5)2

=> 2 = 1(R1/R2)2 = 9 * (6370 / 10)2 = 3.65 * 106 rev/day

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