A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above

Question

A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 56 N or more. He is eager to get the fish to the dock in the shortest possible time.
If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it? A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line that will break under a tension of 56 N or more. He is eager to get the fish to the dock in the shortest possible time.
If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?
If the fish is at rest at the water's surface, what's the least amount of time in which the fisherman can raise the fish to the dock without losing it?

Explanation / Answer

let a is acceleration of the system and g = 9.8 m/s²

F = ma -----> T - mg = ma -----> a = (T/m) - g = (56/5) - 9.8 = 1.4 m/s²

and H is height of the dock from water

H = ½at² -----> t = [2H/a]^½ = [2*2/1.4]^½ 1.69 sec

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