A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a p

Q: A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a p

A) ax = (25-4) / 15 = 1.4 m/s^2 ay = (-3 - 1) / 15 = - 0.27 m/s^2 B) angle = - 10.91 degree C) displacement = ut + 1/2 a t^2 disp in x = 660.8 m disp in y = -77.84 so position w.r.t. rock = ( 676.8 i , -80.24 j )

ID: 2127214 • Letter: A

Question

A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0i -2.40j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (25.0i -3.0j ) m/s.

(a) What are the components of the acceleration of the fish?

ax =

m/s2

ay =

Review the definition of average acceleration and remember that each component is treated separately. m/s2

(b) What is the direction of its acceleration with respect to unit vector ?

Explanation / Answer

A) ax = (25-4) / 15 = 1.4 m/s^2

ay = (-3 - 1) / 15 = - 0.27 m/s^2

B) angle = - 10.91 degree

C) displacement = ut + 1/2 a t^2

disp in x = 660.8 m

disp in y = -77.84

so position w.r.t. rock = ( 676.8 i , -80.24 j )

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A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a p

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A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a p

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