A block of mass m 1 = 4kg slides down a frictionless plane inclined 30 o to the

Question

A block of mass m1= 4kg slides down a frictionless plane
inclined 30o to the horizontal . The block is connected to other block (moving vertically) of mass m2= 4kg by massless string through a rough pulley (with moment of ineria I= 1/2 mR2 , m= 2kg and R= 0.15) as shown in the figure.

Q ) A block of mass m1= 4 kg slides down a frictionless plane inclined 30° to the horizontal . The block is connected to other block ( moving vertically) of mass m2-4kg by massless string through a rough pulley ( with moment of ineria I= ½ mR" , m= 2kg and R=0.15 m) as shown in the fig a) Find the acceleration of the blocks b) Find the acceleration of the pulley c) Find the tension in the string

Explanation / Answer

The force due to gravity is the same on each (mg = 49N)

F= ma

F= m x a

F/m =a

a = 49/4.0 =12.25m/s2

c)

Tension in string: T = 2m1m2g/(m1+m2)

T= (2 x 4x4 x 9.8)/(4+4) =313.6/8 =39.2N

T= 39.2N

b) i have small doubt in following calculation please check

To find the acceleration of pulley is

sigma F = ma

mg- T = ma

49-39.2 = 4xa

a = 9.8/4 = 2.45m/s

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