The figure at the top shows, in cross section, two wires that are straight, para
ID: 1477767 • Letter: T
Question
The figure at the top shows, in cross section, two wires that are straight, parallel, and very long. The ratio i1/i2, of the current carried by wire 1 to that carried by wire 2 is 1/3. Wire 1 is fixed in place. Wire 2 can be moved along the positive side of the x axis so as to change the magnetic energy density uB set up by the two currents at the origin. The lower figure gives uB as a function of the position x of wire 2. The curve has an asymptote of uB = 1.60 nJ/m3 as x goes to infinity, and the horizontal axis scale is set by xs = 84.0 cm.
What is the value of i1?
What is the value of i2?
Explanation / Answer
Given that, xs= 84 cm, total magnetic energy density is zero at x= 28 cm, or x= 2*(84/6).
At this location the magnitudes if magnetic fields are the same. That is
uoi1/2d = uoi2/2*0.12
Hence , d= 0.28*(1/3)=0.09333 M
The relation between field and energy density is,
B1=sqrt (2uBuo)
The magnetic field due to first wire is
B1=uoi1/2d
Use the above two relations we get
i1=2d*sqrt (2uB/uo)
= 29.6*10^-3 A
= 29.6 mA
But we have the below relation,
i2=3i1 = 59.2 mA
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