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The figure at the top shows, in cross section, two wires that are straight, para

ID: 1477767 • Letter: T

Question

The figure at the top shows, in cross section, two wires that are straight, parallel, and very long. The ratio i1/i2, of the current carried by wire 1 to that carried by wire 2 is 1/3. Wire 1 is fixed in place. Wire 2 can be moved along the positive side of the x axis so as to change the magnetic energy density uB set up by the two currents at the origin. The lower figure gives uB as a function of the position x of wire 2. The curve has an asymptote of uB = 1.60 nJ/m3 as x goes to infinity, and the horizontal axis scale is set by xs = 84.0 cm.

What is the value of i1?

What is the value of i2?

Explanation / Answer

Given that, xs= 84 cm, total magnetic energy density is zero at x= 28 cm, or x= 2*(84/6).

At this location the magnitudes if magnetic fields are the same. That is

uoi1/2d = uoi2/2*0.12

Hence , d= 0.28*(1/3)=0.09333 M

The relation between field and energy density is,

B1=sqrt (2uBuo)

The magnetic field due to first wire is

B1=uoi1/2d

Use the above two relations we get

i1=2d*sqrt (2uB/uo)

= 29.6*10^-3 A

= 29.6 mA

But we have the below relation,

i2=3i1 = 59.2 mA

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