if 0.755 kg of lead at a temperature of 255 degree C is dropped into the can, wh

Question

if 0.755 kg of lead at a temperature of 255 degree C is dropped into the can, what is the final temperature of the system if no heat is lost to the surroundings? previous 10 of21 nexd Problem 14.72 Part A A copper calorimeter can with mass 0 815 kg contains 0 185 kg of water and 1 90×10-2 kg of ice in thermal equilibrium at atmospheric If0 755 kg of lead at a temperature of 255 "C is dropped into the can, what is the inal temperature of the system it no heat is lost to the surroundings? pressure. My Anewers Give Ue

Explanation / Answer

we know,

specific heat of lead, C_lead = 128 J/(kg K)

specific heat of copper, C_copper = 386 J/(kg K)

specific heat of water, C_water = 4186 J/(kg K)

latent heat of ice, Lf = 3.33*10^5 J/kg

Let T is the final temperature.

heat lost by lead = heat gained by ice+water+copper

0.755*128*(255 - T) = 0.815*386*(T - 0) + 0.185*4186*(T-0) + 0.019*3.33*10^5 + 0.019*4186*(T - 0)

0.755*128*255 - 0.755*128*T = 0.815*386*T + 0.185*4186*T + 0.019*3.33*10^5 + 0.019*4186*T

0.755*128*255 - 0.019*3.33*10^5 = 0.815*386*T + 0.185*4186*T + 0.019*4186*T + 0.755*128*T

T = (0.755*128*255 - 0.019*3.33*10^5)/(0.815*386+ 0.185*4186 + 0.019*4186 + 0.755*128 )

= 14.48 C

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.