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ID: 1576305 • Letter: I

Question

iew History Bookmarks Develop Window Help 100% Sun Feb 4 3:22:30 ning.com Apple Cloud Yahoo ing Gcogle Wkipedia Geogle Yahco Student-Solu 81118217368 University of California, Merced - PHYS 18- Spring18-LIU:HW: Vectors ng Jump to.. Fernando Periodic Tabie Question 15 of 17 Available From Due Date Points Possible Grade Categor Description: Policies: Sapling Learning A pirbal bounced around its machine before resting between two bumpers. Before the ball came to rest, its displacement (all angies measured counterclockwise from the horizontal x axis was recorded by a series of vectors 83cr, at 90. 55 cm at 149* 63 cm at 221 47 cm at 283 63 om at 21 You can check y You can iew so gi've up on ary q You can keep try until you get it r You lose 5% of th answer in your q attempt at that Uso tho figuro on the right to draw these displacements in order wih the first vector starting at the large and then determine the total displacement's magntude and D eTextbook magnitede- Note: the vector drawing board above should be used to answer the question, but your drawing will not be graded 0 Help With Thi direction O Web Help & V O Technical Sup le 0

Explanation / Answer

x1 = (83 Cos90) i + (83 Sin90) j = 0 i + 83 j

x2 = (55 Cos149) i + (55 Sin149) j = - 47.14 i + 2.58 j

x3 = (63 Cos221) i + (63 Sin221) j = - 47.55 i - 41.33 j

x4 = (47 Cos283) i + (47Sin283) j = 10.57 i - 45.8 j

x5 = (63 Cos21) i + (63 Sin21) j = 58.82 i + 22.58 j

Net displacement is given as

X = x1 + x2 + x3 + x4 + x5 = 0 i + 83 j - 47.14 i + 2.58 j - 47.55 i - 41.33 j + 10.57 i - 45.8 j + 58.82 i + 22.58 j

X = - 25.3 i + 21.03 j

magnitude : sqrt((- 25.3)2 + (21.03)2) = 32.89

direction : 360 - tan-1(21.03/25.3) = 320.3 deg