Draw a proper freebody diagram for the car at the top of the hill (point B). Emp

Question

Draw a proper freebody diagram for the car at the top of the hill (point B).

Employ Newton's Law to find the speed that the car must have at point B such that the normal force acting on the car is 73% of the weight.

Now employ conservation of energy to find the speed required at point A, such that the car passes point B at the required speed. Draw an energy bar graph.

Below answer with the required speed at point A with units of m/s.

Make sure to practise how to explain your work and also how to evaluate your result.

can anyone explain how to do this, and put in all of the mg becuase its confusing me. step by step please

Explanation / Answer

Given that

A roller coaster car of mass (m) =2,494-kilogram

The radius of the circle is (r) =9m

At the point B the net force acting is givne y

Fc =Mg-N

The centripetal force is given by Fc =MvB2/r

Now from the above equations we get

MvB2/r =Mg-73Mg/100

=27Mg/100

Now the speed of the car at point B is given by vB2 =(27/100)*9.81*9m=23.838

then vB =4.88m/s

Now from the law of conervation of energy

Total energy at point A =total energy at point B

(KE)A =(KE)B+(PE)B

(1/2)MVA2 =(1/2)MVB2+Mgh

Then VA2=VB2+4gr =23.838+4*9.81*9 =376.998

The speed of the car at point A is VA =19.416m/s

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.