please help with physics question Phy X www.webassign ne web/Student Assignment-
ID: 1473799 • Letter: P
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please help with physics question
Phy X www.webassign ne web/Student Assignment-Responses submit?dep 2713340 App P MyLab & Mastering Tm San Mateo Count TI-83/84 Plus and TI... Marketing Concepts... c A Free Website Builder... W Free website l Free b... Cannabis Plant Prob... IMMEDIATELY HIRIN... Two-lens systems. The stick figure o (the object) stands on the common central axis of two thin, symmetric lenses. Lens 1 is mounted within the boxed region closer to O, which is at object distance d 1. Lens 2 is mounted within the farther boxed region, at distance d. The table refers to the focal distances fi and f2 for lens 1 and lens 2 respectively, the image distance d 2 for the final image produced by lens 2 (the final image produced by the syste and the overall lateral magnification mitot for the system. All distances are in centimeters. Fi n the missing information, including signs Lens 1 Lens 2 m tot o 1 7.502967 *7.6 Converging *6.5 14 converging signs not given you figure out what's appropriate Describe the image. Select all that apply to receive credit.) real Virtua upright inverted on the same side of lens 2 as object O on the opposite side of lens 2 3:06 PM Ask me anything 11/30/2015Explanation / Answer
here,
for the first lens ,
the object distance , do1 = 14 cm
the focal length , f1 = 7.6 cm
let the image distance be di1
using the lens formula
1/f1 =1/do1 + 1/di1
1/7.6 = 1/14 + 1/di1
di1 = 16.625 cm
for the seccond lens ,
the object distance , do2 = d- di1
do2 = 15.375 cm
the focal length , f2 = 6.5 cm
let the image distance be di2
using the lens formula
1/f2 =1/do2 + 1/di2
1/6.5 = 1/15.375 + 1/di2
di2 = 11.26 cm
mtot = ( -di1/do1) * ( - di2/do2)
mtot = ( 16.625/14) * ( 11.26/15.375)
mtot = 0.87
the image is real , upright and on the opposite side of the lens 2
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