A 4.00-kg mass and a 3.00-kg mass are attached to opposite ends of a very light

Question

A 4.00-kg mass and a 3.00-kg mass are attached to opposite ends of a very light 42.0-cm-long horizontal rod (the figure). The system is rotating at angular speed = 5.45 rad/s about a vertical axle at the center of the rod.
(Figure 1)

Part A

Determine the kinetic energy KE of the system.

Express your answer using three significant figures and include the appropriate units.

Part B

Determine the net force on 4.00-kg mass.

Express your answer using three significant figures and include the appropriate units.

Part C

Determine the net force on 3.00-kg mass.

Express your answer using three significant figures and include the appropriate units.

Figure 1 of 1

A 4.00-kg mass and a 3.00-kg mass are attached to opposite ends of a very light 42.0-cm-long horizontal rod (the figure). The system is rotating at angular speed = 5.45 rad/s about a vertical axle at the center of the rod.
(Figure 1)

Part A

Determine the kinetic energy KE of the system.

Express your answer using three significant figures and include the appropriate units.

K =

Part B

Determine the net force on 4.00-kg mass.

Express your answer using three significant figures and include the appropriate units.

FA =

Part C

Determine the net force on 3.00-kg mass.

Express your answer using three significant figures and include the appropriate units.

FB =

Figure 1 of 1

Explanation / Answer

V = R*omega = 0.21 m * 5.45 = 1.1445 m/s

kinetic energy KE = 1/2*4*1.14452 + 1/2*3*1.14452

= 4.58458 J

Net force on 4 Kg

F = mv2  / 0.21 = 4*1.14452 / 0.21 = 24.9501 N

net force on 3 kg

F = 3*1.14452 / 0.21 = 18.712575 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.