Please put the right answer and work out problem thank you In the figure a 140-t

Question

Please put the right answer and work out problem

thank you

In the figure a 140-turn coil of radius 5.00 cm and resistance 3.00 ohm is placed around a smaller diameter solenoid (d = 3.20 cm). The long solenoid in the figure has 220 turns per centimeter and carries a current of 1.40 A. The current in the solenoid is reduced to zero and then increased to -1.40 A in a time of 6.00 times I0^-2 s. What is the magnitude of the induced current in the outer coil while the solenoid current is being changed

Explanation / Answer

Here ,

radius of solenoid , r = 3.2/2

r = 1.6 cm

number of truns in solenoid , n = 220 /cm = 22000 /m

Now , for the emf induced in the coil ,

emf = change in flux/time

emf = 140*pi *0.016^2 * u0 * 22000 * (1.4 - 0)/(6 *10^-2)

emf = 0.0726 V

current induced = emf/R

current induced = 0.0726/3

current induced =0.0242 A

the current induced in the coil is 0.0242 A

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