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Please provide with step by step solution thank you! Accepted characters: number

ID: 1839298 • Letter: P

Question

Please provide with step by step solution thank you!

Accepted characters: numbers, decimal point markers (period or comma), sign indicators (-), spaces (e.g., as thousands separator, 5 000), "E" or "e" (used in scientific notation). Complex numbers should be in the form (a + bi) where "a" and "b" need to have explicitly stated values. For example: {1+1i} is valid whereas {1 +i} is not. {0+9i} is valid whereas {9i} is not. Given: All components are ideal. V_m = 240 Vrms at 120 Flz Output Resistor R = 10 Ohm Determine the average of the output voltage V_0. Determine the rms of the of output voltage v_0. Determine the average load current through R. Determine the average power absorbed by the load R. Determine the power factor of the circuit.

Explanation / Answer

From the above circuitry it is obvious that Half wave rectification is going on for the volate provided.

For the Half wave rectifier, the Average voltage = Vavg= 0.318Vpk

a) Given, Vrms = 240Volts at 120Hz.

Now Vpk = sqrt2 X Vrms = 240 X 1.41421 = 339.411 Volts

Therefore Vavg is 0.31830988 x 339.411 = 108.0378768 Volts

b) Vrms of output = Vrms= Vpk/2 = 339.411/2 = 169.7055 Volts

c) Load current through R is Vavg / R = 108.0378768 / 10 = 10.803787 Amperes

d) Average power is Vavg (Full wave) X Iavg = 266.5 x 10.803787 = 2879.809 Watts

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