PART C: ignoring friction, what will be the position (angle in radians) of the p

Question

PART C: ignoring friction, what will be the position (angle in radians) of the pendulum at t=540s? Problem 11.34 You c this assignment gnoring friction, what will be the postion (angle in Express your answer using two significant figures radians) of the penduum att 025 A clock pendulum at an angle of 15 to the vertical. oscillates at a frequency of rad Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Part B gnoring friction, what will be the position (angle in radians) of the pendulum att 1.60s Express your answer using two significant figures rad

Explanation / Answer

period of the pendulum is T = 1/f = 1/2.5 = 0.4 S

angular frequency w = 2*pi/T = 2*3.142/0.4 = 15.71 rad/s

back to back the angle swept is 15+15 = 30 degrees

in 0.4 sec it covrers 30 degrees

then in 0.25s it covers 0.25*30/0.4 = 18.75 degrees

18.75-15 degrees = 3.75 degrees to the left of the vertical if it was started form right of the vertical

3.75 degrees are (2*pi*3.75/360) = 0.065 rad

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at t =1.5 s,the angle is 1.5*30/0.4 = 112.5 degrees - (90+15) = 7.5 degrees

7.5 degrees are 2*3.142*7.5/360 = 0.1309rad to the left of theverticle

at = 540 s

the angle is 540*30/0.4 = 40500 degrees/30 = 1350 oscillations exactly

the pendulum is at right expreme position

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