a single conservative force working on a 2 kg particle along x-axis changes its

Question

a single conservative force working on a 2 kg particle along x-axis changes its position from x= 5m to x = 9m if work done by force is 4J and the particle starts from rest at x = 5m, speed of The particle at x= 9 m is? a single conservative force working on a 2 kg particle along x-axis changes its position from x= 5m to x = 9m if work done by force is 4J and the particle starts from rest at x = 5m, speed of The particle at x= 9 m is? a single conservative force working on a 2 kg particle along x-axis changes its position from x= 5m to x = 9m if work done by force is 4J and the particle starts from rest at x = 5m, speed of The particle at x= 9 m is?

Explanation / Answer

work done = change in kinetic energy

4 = 0.5 * mass * final velocity^2 - 0.5 * mass * initial velocity^2

4 = 0.5 * 2 * final velocity^2 - 0.5 * 2 * 0^2

4 = 0.5 * 2 * final velocity^2

final velocity = 2 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.