Laser light of wavelength 420 nm is incident on a circular aperture which has a
ID: 1467592 • Letter: L
Question
Laser light of wavelength 420 nm is incident on a circular aperture which has a diameter of 0.021 mm.
A diffraction pattern is observed on a screen which is placed 82 cm from the aperture.
NEED HELP WITH SECOND PART ONLY
NEED HELP WITH SECOND PART ONLY
NEED HELP WITH SECOND PART ONLY
NEED HELP WITH SECOND PART ONLY
the answer is not 1.64 cm
Laser light of wavelength 420 nm is incident on a circular aperture which has a diameter of 0.021 mnm A diffraction pattern is observed on a screen which is placed 82 cm from the aperture. Give your answer to at least three significant figures. Answer must be accurate to 1%. what is the diffraction angle, , of the first diffraction minimum? 1.398156 degrees You are correct. Previous Tries What is the distance, on the screen, from the center of the central bright spot to the first dark ring? 1.98 cm Sueomit Anauer Incorrect. Tries 10/20 Previous Tries Submit Answer Incorrect. Tries 10/20 Previous TriesExplanation / Answer
part B
In diffraction pattern
the needed equation is Y = mLR/d---------------1
and d sin theta = mL--------------------2
where L = wavelgnth
m = order = 1,2,3,4, ......... for brigth bands
m = 1.5, 2.5, 3.5, 4.5, ......for dark bands
R is the distance from slit to screen
Y = disatnce from central spot to nth order fringe or fringe width
so here now we apply
Y = 1.5 * 420 e-9 * 0.82/(0.021 e -3)
Y = 2.46 cm
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