The circuits shown below contain identical bulbs and non-identical ideal batteri
ID: 1466481 • Letter: T
Question
The circuits shown below contain identical bulbs and non-identical ideal batteries. When a student sets up the circuits shown below, she observes that bulb A is brighter than bulb B.
By this observation the student concludes that the voltage across bulb A is ---Select--- greater than the voltage across bulb B. less than the voltage across bulb B. equal to the voltage across bulb B. Not enough information given.
A second bulb is added to each circuit as shown below.
The student notices that bulb A is now equal in brightness to bulb B. In terms of the voltage V2 across battery 2, the voltage V1 across battery 1 is
4V2, 2V2, 2V2/,V2 V2/2,V2/2,V2/4
The batteries are now swapped, as shown below.
The brightness of bulb A is now ---Select--- greater than the brightness of bulb B. equal to the brightness of bulb B. less than the brightness of bulb B. Not enough information given.
Explanation / Answer
(1)
In this case, the voltage across bulb A is greater than voltage across bulb B. Becasuse, A is brighter than B , implies that more current pass through A and it results in more voltage in accordace with Ohm's law. ( current is proportinal to voltage )
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(2)
In this case, both are equal bright. As another bulb is connected in parallelm the voltage in the second circuit be halved.V 2 /2
As current is same ( brightness ) , It implies that V1 = 2 V2
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In this case, batteries are swapped, The battery connected to B is at high voltage hence it is brighter than A
Thus, the brightness of A is less than brightness of B.
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