A converging lens has a focal length of f- 23.0 cm (A) An object is placed p1 =

Question

A converging lens has a focal length of f- 23.0 cm (A) An object is placed p1 = 69.0 cm from the lens. Construct a ray diagram, find the image distance, and describe the image IF O 9 (B) An object is placed p2 23.0 cm from the lens. Find the image distance and describe the image An image is formed by a converging lens. (a) The object is farther from the lens than the focal point. (b) The object is closer to the lens than the focal point (C) An object is placed p3 11.5 cm from the lens. Construct a ray diagram, find the image distance, and describe the image SOLVE IT 69.0 cm from the lens. Construct a ray diagram, find the image distance, and (A) An object is placed p describe the image Conceptualize: Because the lens is converging, the focal length is positive. We expect the possibilities of both real and virtual images Categorize: Because the object distance is larger than the focal length, we expect the image to be real The ray diagram for this situation is shown in figure (a) Analyze: Find the image distance 23.0 cm 69.0 cm 91 = 1.0289 cm Find the magnification of the image: 0289 Did you accidentally divide or take the inverse in your calculation? cm 69.0 cm

Explanation / Answer

FOR A, IMAGE DISTANCE CAN BE CALCULATED USING FORMULA-

1/f = 1/v - 1/u

1/23 = 1/v - 1/(-69)

1/23 = 1/v + 1/69

1/v = 1/23 - 1/69

1/v = 2/69

v = 69/2

v = 34.5 cm right to the lens

magnification = - 34.5/69

M = - 0.5

C> for third case -

1/f = 1/v - 1/u

1/23 = 1/v - 1/(-11.5)

1/23 = 1/v + 1/11.5

1/v = 1/23 - 1/11.5

1/v = -1/23

v = - 23 cm

image will be 23 cm left to the lens.

M = -23/-11.5

M = 2

IT WILL BE IMAGINARY

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