it takes a force of 46 kN on the lead car of a 16-car passenger train with mass
ID: 1462750 • Letter: I
Question
it takes a force of 46 kN on the lead car of a 16-car passenger train with mass 9.1×105kg to pull it at a constant 42 m/s on level tracks.
1)What power must the locomotive provide to the lead car?
2)How much more power to the lead car than calculated in part A would be needed to give the train an acceleration of 1.2 m/s2 , at the instant that the train has a speed of 42 m/s on level tracks?
3)How much more power to the lead car than that calculated in part A would be needed to move the train up a 1.5% grade (slope angle =arctan 0.015) at a constant 42 m/s ?
Explanation / Answer
1) Power provided by the locomotive, P = F*v
= 46*10^3*42
= 1932000 Watts
2) extra power provided = F'*v
= m*a*v
= 9.1*10^5*1.2*42
= 45864000 W
3) alfa = tan^-1(0.015)
= 0.8594 degrees
extra power provided = F'*v
= m*g*sin(alfa)*v
= 9.1*10^5*9.8*sin(0.8594)*42
= 5617890 W
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.