A jet plane is flying at a constant altitude. At time t1=0 it has components of

Question

A jet plane is flying at a constant altitude. At time t1=0 it has components of velocity vx= 88 m/s , vy= 114 m/s . At time t2= 31.5 s the components are vx= 162 m/s , vy= 41 m/s .

Part A

For this time interval calculate the average acceleration.

Give your answer as a pair of components separated by a comma. For example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. Express your answer using two significant figures.

Part B

Find the magnitude of the average acceleration.

Express your answer using two significant figures.

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Part C

Find the direction of the average acceleration (let the direction be the angle that the vector makes with the +x-axis, measured counterclockwise).

Explanation / Answer

We know average acceleartion = change in velocity/time

Change in velocity in x direction = 162-88 = 74

Hence, x component of average acceleration = 74/31.5 = 2.35 = 2.4m/s^2

Change in velocity in y direction = 41-114 = -73

Hence, y component of average acceleration = -73/31.5 = -2.32= -2.3m/s^2

PartA: Hence average acceleration is (2.4, -2.3)

PartB: Magnitude of average acceleration is sqrt(2.4^2+2.3^2) = 3.3m/s^2

PartC: Direction of average acceleration = tanA = y/x , where A is the angle that it makes with positiove x axis counterclockwise.

=> A = arctan(-2.3/2.4) = arctan(-0.958) = -43.8 degrees

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