two samples of water were mixed yielding a 28 degree mixture. the cold water was
ID: 1457873 • Letter: T
Question
two samples of water were mixed yielding a 28 degree mixture. the cold water was initially 20 degrees Celsius. there was 1.5 times as much hot water as cold water. what was the initial temperature of the hot water? two samples of water were mixed yielding a 28 degree mixture. the cold water was initially 20 degrees Celsius. there was 1.5 times as much hot water as cold water. what was the initial temperature of the hot water? two samples of water were mixed yielding a 28 degree mixture. the cold water was initially 20 degrees Celsius. there was 1.5 times as much hot water as cold water. what was the initial temperature of the hot water?Explanation / Answer
Tmixture = [mhotThot+mcoldTcold] / [mhot+mcold]
28oC = [mhotThot+1.5*mhot*20oC] / [mhot+1.5*mhot]
28oC = [Thot+30] / 2.5
Thot = 70 - 30 = 40oC
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