a ferris wheel with radius 14.0 m is turning about a horizontal axis through its

Question

a ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The wheel is turning in a constant speed. The passenger spends 12.56 second on one revolution. what is the radial speed of this ferris wheel. what is the direction and magnitude of the passenger's acceleration when she passes lowest point in her circular motion? what is the direction and magnitude of the passengers acceleration when she passes highest point in her circular motion. what will be the new radial speed of the wheel if she just feels weight loss when she passas the highest point can you find a place where the result force of that passenger is zero. why or why not

Explanation / Answer

First of all, this term "Radial speed" make no sense as the objects are not moving radially. So I am callingangular speed instead.

angular speed, w = 2 pi/T = 6.28/12.56 s= 0.5 /s

speed, v = wr = 0.5*14 = 7 m/s

acceleration, a = w^2 r = 0.5*0.5*14 = 3.5 m/s^2 towards center

acceleration when she passes lowest point in her circular motion = 3.5 m/s^2 upward

acceleration when she passes highest point in her circular motion = 3.5 m/s^2 downard

she will feel weight loss when acceleration is g=9.8 m/s2

w^2 r = 9.8

w = sqrt (9.8/14) =0.837 / s

No the resultant force is never zero because the passenger is performing the circular motion which means the resultant force of Normal reaction and gravitation is Mw^2 r

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