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answer the quentions and explain. 4.all 90% 12:49 PM 5 1. If an electron is defl

ID: 1456127 • Letter: A

Question


answer the quentions and explain.

4.all 90% 12:49 PM 5 1. If an electron is deflect od by an electric fiold af 250 V/m, what is tha accalaration of this deflection? Finally the last two prablems should giva you an idea of what I consider in dapth cal culation problems sound level al a punl LO m from a port The sound level al a poinIP is l4 clb below source. What is the distancc from the source to point P?. 1. The sound level al a poinl P is 14 db below he sounl level au a poinl 1.0 m from a poin . 2. A 5.)-C charge is 1 m from a 2.U-C charge on the x-axis if a point charge of-is 1-C Charge

Explanation / Answer

1) F = q*E = 1.6*10^-19*250 = 4*10^-17 N

m*a = 4*10^-17

accelaration a = (4*10^-17)/(9.11*10^-31) = 4.4*10^13 m/s^2

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2)the Sound level at a point P is 14db below the sound level at a point 1 m from a point source


Intensity I is proportional to 1/r^2


I1/I2 = (r2/r1)^2

r2/r1 = sqrt(I1/I2)


I1/I2 = 10^(1.4) = 25.12

then


r2/r1 = sqrt(25.12) = 5.012

r2 = 5.012*r1 = 5.012 m = 5m

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3) let 2C is at the origin

then force on 1C due to 5C is F1 = k*q1*q2/r^2 =(9*10^9*5*1)/(15^2) = 2*10^8 N


Force on 1C due to 2C is F2 = k*q2*q3/r^2 = (9*10^9*2*1)/(5) = 3.6*10^9 N

net force is F1+F2 = (3.6+0.2)*10^9 = 3.8*10^9 N