You have two polarizers on an optical rail between an unpolarized light source (
ID: 1455345 • Letter: Y
Question
You have two polarizers on an optical rail between an unpolarized light source (of intensity I_0) and a detector. Polarizer 1 is oriented at an angle of theta_1 = 40degree from the horizontal, and polarizer 2 is oriented horizontally (theta_2 = 0degree). (a) What is the intensity of the light after it passes through only polarizer 1? Express your answer as a fraction or decimal in terms of I_0 (i.e. I = 1/4 I_0). (b) What is the intensity of the light after it has passed through both polarizers? Again, express your answer as a fraction or decimal in terms of I_0.Explanation / Answer
when an unpolarized light passes through a first polarizer then it intensity became half is
I = Io /2 .............answer
now this light after passing from 1st is polarized light with 40 degree horizontal
so apply Malus's law
I = Ii* [cos( 40-0) ]^2
= Io/2 * [cos( 40) ]^2
= 0.293*Io .............answer
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