exiting from a small linear accelerator near Washington D.C., a proton is moving
ID: 1454646 • Letter: E
Question
exiting from a small linear accelerator near Washington D.C., a proton is moving parallel to the ground. What should the direction(s) of its velocity be in order to maximize the upward component of the Earth's magnetic force on it? Using a value of .05 mT for the horizontal component of the Earth's magnetic field at this location, what is the upward acceleration of the proton as it exits the accelerator at a speed of 2000 m/s? exiting from a small linear accelerator near Washington D.C., a proton is moving parallel to the ground. What should the direction(s) of its velocity be in order to maximize the upward component of the Earth's magnetic force on it? Using a value of .05 mT for the horizontal component of the Earth's magnetic field at this location, what is the upward acceleration of the proton as it exits the accelerator at a speed of 2000 m/s? exiting from a small linear accelerator near Washington D.C., a proton is moving parallel to the ground. What should the direction(s) of its velocity be in order to maximize the upward component of the Earth's magnetic force on it? Using a value of .05 mT for the horizontal component of the Earth's magnetic field at this location, what is the upward acceleration of the proton as it exits the accelerator at a speed of 2000 m/s?Explanation / Answer
Given,
v = 2000 m/s ; Bx = 0.05 mT = 0.05 x 10-3 T
Let a be the acceleration.
We know that the magnetic force on a moving charge is given by:
F = q v B Also F = ma
ma = q v B
a = q v B/m
a = 1.6 x 10-19 x 2000 x 0.05 x 10-3 / 1.67 x 10-27 = 9.5 x 106 m/s2
Hence, a = 9.5 x 106 m/s2
We know that the magnetic force on the moving charge is perpendicular to both the velocity and magnetic field.
From right hand rule, If magnetic field is upwards(fingers), the charge is moving parallel to ground(thumb), it will get diverted to follow a curve path because of the magnetic force. The magnetic force will be along the direction of palm.
The force will be max when the positive charge will move clockwise.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.