An electron experiences the greatest magnetic force when it is moving northward

Question

An electron experiences the greatest magnetic force when it is moving northward in a uniform magnetic field of strength B = 1.5 T. The force. F_B is vertically downward and of magnitude 7.0 times 10^-13 N. The only force acting on the electron is the magnetic force. What is the direction of the magnetic field? Draw and label a vector in the figure above to indicate the direction of the magnetic field (2) What a the speed of the electron? Is the velocity of the electron constant? Explain your answer. What is the radius of the circular path of the electron?

Explanation / Answer

magnetc force Fb = q*(v x B)

F = 7*10^-13 -k N

v = v j

B = ?

q = -1.6*10^-19 C

from Fb = q*(v x B)

-k = -(j x ?)

? = -i

magnetic field is towards east

b)

Fb = q*V*B

7*10^-13 = 1.6*10^-19*v*1.5

v = 2.92*10^6 m/s <<-----answer

+++++++

velocity is constant

the force is perpendicular to motionof velocity

Work = 0

from work energy theorem work = change inKE

change in KE = 0

speed is conatant

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