Objects with masses of 225 kg and a 525 kg are separated by 0.390 m. (a) Find th

Question

Objects with masses of 225 kg and a 525 kg are separated by 0.390 m. (a) Find the net gravitational force exerted by these objects on a 44.0-kg object placed midway between them. magnitude Incorrect: Your answer is incorrect. . Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N direction ---Select--- toward the 225-kg mass toward the 525-kg mass The magnitude is zero. Correct: Your answer is correct. . (b) At what position (other than infinitely remote ones) can the 44.0-kg object be placed so as to experience a net force of zero? Incorrect: Your answer is incorrect. .

Explanation / Answer

a)
Force due to each mass will be in opposite direction
Net force will be difference of these forces
Net force will be directed towards smaller mass

r1 = r2 = 0.390/2 = 0.195 m

Fnet = G*m*(m1/r^2 - m2/r2^2)
= (6.673*10^-11)* (525/0.195^2 - 225/0.195^2)
= 5.26*10^-7 N
Answer: 5.26*10^-7 N

toeards 225 kg mass

b)
This point will lie between them
let the point is x m from 525 kg
r1= x
r2 = 0.390-x

net force = 0
F1 = F2
G*m*m1/r1^2 = G*m*m2/r2^2
m1/r1^2 = m2/r2^2
525/(x)^2 = 225/(0.390-x)^2
{x/(0.390-x)}^2 = 225/525
x/(0.390-x) = 0.655
x = 0.255 - 0.655x
1.655 x = 0.255
x = 0.154 m
It must be placed at a distance of 0.154 m from 525 kg mass

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