Objects with masses of 225 kg and a 525 kg are separated by 0.360 m. (a) Find th

Question

Objects with masses of 225 kg and a 525 kg are separated by 0.360 m.

(a) Find the net gravitational force exerted by these objects on a 64.0-kg object placed midway between them.

Objects with masses of 225 kg and a 525 kg are separated by 0.360 m (a) Find the net gravitational force exerted by these objects on a 64.0-kg object placed midway between them. magnitude directionSelec (b) At what position (other than infinitely remote ones) can the 64.0-kg object be placed so as to experience a net Your response differs from the correct answer by more than 10%. Double check your calculations. N force of zero? m from the 525-kg mass

Explanation / Answer

a) force due to 225 kg object = Gm1m2/r^2

F1 = 6.67*10^-11*225*64/0.18^2

F1 = 0.0002964N

Force due to 525kg object = 6.67*10^-11*525*64/0.18^2

F2 = 0.000069N

Net force = F2 -F1 = 6.9*10^-4 - 2.9*10^-4 = 4*10^-4 N away from mass 525kg

b) let the point at which the mass 64 kg experiences a zero net force be at a distance x from 525 kg

Force due to 525kg = force due to 225 kg

G*525*64/x^2 = G *225*64/(0.36-x)^2

225x^2 = 525x^2 +68.04 -378x

300x^2 -378x +68.04 = 0

x = 378 -sqrt(378^2 - 4*300*68.04) / 600

x = 0.217 m

The net force will be zero at a distance 0.217m from 525kg

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