The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pig

Question

The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at 16.3 m/s, when the eagle swoops down, grabs the pigeon, ancfflies off. At the instant right before the attack, the eagle is flying toward the pigeon at an angle theta = 35.9degreebelow the horizontal, and a speed of 34.7 m/s. What is the speed of the eagle immediately after it catches its prey? What is the magnitude of the angle, measured from horizontal, at which the eagle is flying immediately after the strike?

Explanation / Answer

Before the collision(pick up)

momentum of the eagle; horizontal= 2m*34.7*cos(35.9)=56.22m i^ ; vertically = 2m*34.7*sin(35.9) =-40.69m j^

(-) means downward

momentum of the system= (56.22m +16.3m)i^ -40.69m j^ =(72.52m)i^ -40.69m j^

After the catch up, system's mass= 2m+m =3m. Take velocity as 'v' and angle from the horizon 'x'

Now after the catch up, momentum of the system; apply conservation of linear momentum

vertically, (3m)*vsin(x) =40.69m-----(1)

horizontally, (3m)*vcos(x)=72.52m---(2)

(1)/(2) ; tan(x)= 0.561

x=29.2960

from (1) , v=27.72 ms-1

                               

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