The mass in the figure is released from rest at a height of 5.00 m above on a cu
ID: 1486183 • Letter: T
Question
The mass in the figure is released from rest at a height of 5.00 m above on a curved frictionless ramp. At the foot of the ramp is a spring of force constant k = 400. N/m. The object slides down the ramp and into the spring, compressing it a distance x before momentarily coming to rest. Find x. After coming to rest, the spring gives the mass back all of the kinetic energy it had when they first came into contact. On the way back there is a drag force of 5 N on the mass. How far does it slide under the influence of this force before coming to a stop? (Assume it's on horizontal ground the whole way.)Explanation / Answer
conservation of energy
mgh = 0.5*kx^2
3*9.8*5 = 0.5*400*x^2
x = 0.857 m
b) KE = drag force*d
0.5*kx^2 = F*d
0.5*400*0.857^2 = 5*d
d = 29.4 m
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