Peter, a 100 kg basketball player, lands on his feet after completing a slam dun

Question

Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk then immediately jumps up again to celebrate his basket. When his feet first touch the floor after the dunk, his velocity is 4 m/s downward. His velocity is 5 m/s upward when his feet leave the floor 0.60 s later. (a) What is the impulse exerted on Peter during the 0.60 s his is in contact with the ground? (b) What is the average net force exerted on Peter during this 0.60 s? (c) What is the average reaction force exerted upward by the floor on Peter during this 0.60 s?

Explanation / Answer

a)

Impulse = change in momentum

Impulse = m (5+4)

Impulse = 900kgm/s

b)

Average net force = impulse/time

Fnet = 900/0.6

Fnet= 1500N

c)

Fnet = N -mg

N= Fnet +mg

N= 2480N

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