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1.) When an object gets charged by rubbing, where does the electric charge origi

ID: 1452199 • Letter: 1

Question

1.) When an object gets charged by rubbing, where does the electric charge originate?

     a.the air surrounding the object

     b. created by the rubbing energy

     c. the process leads to a redistribution of charge, not the creation of charge

2.) Identically charged obkects A and B are seperated by a distance d. You measure the force F that A exerts on B. if you now separate the objects by distance 1.4d, what will be the new force A exerts on B?

     a. 1.4F

     b. 2.0F

     c. 1/2 F

     d. 1/1.4 F

     e. F

3.) Balloon has charge q. and identical mass balloon B has charge 10q. You hang them from threads near eachother.Choose all statements which you agree.

     a. the force that A exerts on B is 1/10 the force that B exerts on A.

     b. the force that A exerts on B is 10 times the force that B exerts on A.

     c. A and B exert the same magnitude forces on eachother

     d. The angle between the thread supporting A and the vertical is less than the angle between the thread supporting B and the vertical.

4.) Two objects with charges +q and -2q are seperated by a distance r. You slowly more one of the objects closer to the other so that the distance between them decreases by half. Considering the two objects as the system, which statements are incorrect?

     a. The electrical potential energy of the system doubles

     b. The electrical energy potential of the system decreases by half

     c. The magnitude of the electric potential energy doubles

     d. The magnitude of the electric potential energy decreases by half

5.) Two small objects, each with charge +5.0 x 10^-9 C are seperated by a distance of 50cm. What is the magnitude and direction of the electrical force that they exert on an identical third object that is 50cm from each of them?

    

Explanation / Answer

1)the process leads to a redistribution of charge, not the creation of charge.(option C )

2)
F=1/r2
1/1.42=1/2
FB=1/2F (option C )

3) A and B exert the same magnitude forces on eachother (option C )

4)option A and B

a. The electrical potential energy of the system doubles

     b. The electrical energy potential of the system decreases by half

5)F = Kc q1 q2 / r2
Kc = 8.99x109 N*m^2/C^2
q1=q2=+5.0 x 10-9 C
F=8.99x109 x5.0 x 10-9 x5.0 x 10-9 /.52

F=8.99 N it will attract the third force