Pure-breeding strains of two mutant panthers were developed in different zoos. N

Question

Pure-breeding strains of two mutant panthers were developed in different zoos. Neither mutant makes hair pigment, so the hair is transparent and the fur appears to be pink rather than the normal black. When each mutant was crossed to homozygous black panthers, the F1 were always black no matter which parent was pink. The mutants were called pink-1 (pk-1) and pink-2 (pk-2) for convenience, but it was not known whether they were mutations of the same gene or mutations in different genes.
C: What would be the result of a cross between pink-1 and pink-2 if the two mutations were in different genes? Include the genotypes of the panthers in your answe D: What phenotypic ratio would occur in the F2 generation if the two mutations were in different genes


Pure-breeding strains of two mutant panthers were developed in different zoos. Neither mutant makes hair pigment, so the hair is transparent and the fur appears to be pink rather than the normal black. When each mutant was crossed to homozygous black panthers, the F1 were always black no matter which parent was pink. The mutants were called pink-1 (pk-1) and pink-2 (pk-2) for convenience, but it was not known whether they were mutations of the same gene or mutations in different genes.
C: What would be the result of a cross between pink-1 and pink-2 if the two mutations were in different genes? Include the genotypes of the panthers in your answe D: What phenotypic ratio would occur in the F2 generation if the two mutations were in different genes


Pure-breeding strains of two mutant panthers were developed in different zoos. Neither mutant makes hair pigment, so the hair is transparent and the fur appears to be pink rather than the normal black. When each mutant was crossed to homozygous black panthers, the F1 were always black no matter which parent was pink. The mutants were called pink-1 (pk-1) and pink-2 (pk-2) for convenience, but it was not known whether they were mutations of the same gene or mutations in different genes.
C: What would be the result of a cross between pink-1 and pink-2 if the two mutations were in different genes? Include the genotypes of the panthers in your answe D: What phenotypic ratio would occur in the F2 generation if the two mutations were in different genes

Explanation / Answer

in dihybrid cross the mutants show incompatibility domince in pink and black color and further test is test cross i which the reccesive trait is crossed by the f1 generation in which follow like this

A test cross is a valuable tool in predicting the genotype of the organism in question. The test cross method was developed by the father of genetics, Mendel. The goal in a test cross is to discover if the genotype is homozygous dominant (AA) or heterozygous (Aa). Both genotypes produce the dominant phenotype (characteristic) so it is impossible to tell just by looking. This is were the test cross comes into play. A test cross is simple and extremely helpful in discovering if a organism is true breeding. For example AA or aa would be a true breeding trait, when AA is crossed with AA it produces AA. A true breeding trait would be one necessary to use in a monohybrid cross with another true breeding trait to produce the F1, filial generation. To perform a test cross a homozygous recessive trait (aa) must be used to cross with the unknown genotype. There will be only two possible results. If the unknown (A-) dominant genotype happens to be homozygous dominant (AA) than all of the offspring produced will be Aa.

AA (unknown) X aa (known homozygous recessive trait) = 4 Aa's (heterzygotes)

Using the Punnett Square:

On the other hand if the mystery individual A- is heterozygous (Aa) then the offspring produced will be 50% homozygous recessive and 50% heterozygous.

Aa (unknown) X aa (known homozygous recessive trait) = 2 aa's (recessive homozygote) and 2 Aa's (heterzygote)

Using the Punnett Square:

Summary Chart of the two paths test crossing can take using the pea plant flower:

Explanation: A homozygous recessive genotype used is pp in this test cross. The phenotype for pp is a pink pantherThe domiant phenotype will be a black but the actual genotype is unknown until the cross is performed

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.