A 1-ton load (2,000 pounds) is supported by two cables, making angles with the h
ID: 1451747 • Letter: A
Question
A 1-ton load (2,000 pounds) is supported by two cables, making angles with the horizontal, respectively, equal to 60 degree and 30 degree as shown in Fig. 2. Determine the tension in the two cables, i.e., determine the magnitude of the forces F_1 vector and F_2 vector. In the figure, the weight is illustrated with the force vector F_3. |F_1 vector| approximately equal 1724 lbs.; |F_2 vector| approximately equal 1000 lbs. |F_1 vector| approximately equal 1000 lbs.; |F_2 vector| approximately equal 724 lbs. |F_1 vector| approximately equal 1233 lbs.; |F_2 vector| approximately equal 1105 lbs. |F_1 vector| approximately equal 1847 lbs.; |F_2 vector| approximately equal 1236 lbs. |F_1 vector| approximately equal 1236 lbs.; |F_2 vector| approximately equal 1747 lbs.Explanation / Answer
a) |F1| = 1724 lbs, |F2| = 1000 lbs
2) As the load is in equilibrium, net force and net torque acting on the load must be zero.
Let F1 and F2 are the two forces.
Apply, Fnetx = 0
F1*cos(60) - F2*cos(30) = 0
F2 = F1*cos(60)/cos(30)
F2 = 0.577*F1 ---(1)
Apply, Fnety = 0
F1*sin(60) + F2*sin(30) - m*g = 0
F1*sin(60) + 0.577*F1*sin(30) = m*g
1.1547*F1 = 2000
F1 = 2000/1.1547
F1 = 1732 lbs <<<<<<---------Answer
from equation 1
F2 = 0.577*1732
= 1000 lbs <<<<<<---------Answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.