A 1,220-kg car traveling initially with a speed of 25.0 m/s in an easterly direc

Question

A 1,220-kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 8,500-kg truck moving in the same direction at 20.0 m/s (see figure below). The velocity of the car right after the collision is 18.0 m/s to the east. (a) What is the velocity of the truck right after the collision? 1 . m/s (east) (b) How much mechanical energy is lost in the collision? (Use input values with an adequate number of significant figures to calculate this answer.) 2 . kJ

Explanation / Answer

Speed of the truck after the collision is given by m(c) . v(c) + m(t) . v(t) = m(c) . V (c) + m(t) . V(t) 1115 . 25 + 9400. 20 = 1115 . 18 + 9400 . V(t) V(t) = 20.83 m/s KE lost = KE before – KE after KE lost = (1/2 . 1115 . 25^2 + 1/2 . 9400 . 20^2) – ( 1/2 . 1115 . 18^2 + 1/2 . 9400 . 20.83^2 )

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