?For a spherical density anomaly shown below, sketch the gravity anomaly observe

Question

?For a spherical density anomaly shown below, sketch the gravity anomaly observed on the surface. Estimate the gravity anomaly observed at A and B. The volume of a sphere is 4/3pir^3 and the gravitational constant is 6.67E-11 m^3/Kgs^2

surface. Estimate the gravity anomaly observe Tr' and the gravitational constant is 6.67% 10.' AB=0.5 km m2 p=2700 kg/ Th=1 km =200 m p=2000 kg/m3 Assuming there is a ring shape circular tunnel lius of the ring is 50 meters and the radius of t e expected gravitational anomaly at the surface As shown below, the Southern Rockies have a

Explanation / Answer

Given that

The volume of a sphere is 4/3pir3

And the gravitational constant is (G) = 6.67E-11 m^3/Kgs^2

Therefore from the given figure the gravity anomaly at point A and B is

gA =GM/rA2 =(6.67*10-11)(4/3)(pi)r3*p/(200+1000)2 =3.1*10-6m/s2

gB =GM/rA2+rB2 =(6.67*10-11)(4/3)(pi)r3*p/(1200)2+(500)2 =3.1*10-6m/s2

Expected gravitational anomaly on the top of the center of the ring is

g' =GMr/R3

    =(6.67*10-11)(4/3)(pi)R3*p(100)/R3=5.6*10-5m/s2

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