Kevi Th https:// ust 35nc.theexpertta.com Common/TakeTutorialAssignment.aspx App
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Kevi Th https:// ust 35nc.theexpertta.com Common/TakeTutorialAssignment.aspx Apps WeBwork Spring20 WeBWork Spring careers in SE Quiz 10 Ampere's Law Begin Date: 4/1/2016 12:00:00 AM Due Date: 4/1/2016 59:00 PM End Date: 4/1/2016 59:00 PM (50%) Problem 2: A solenoid is created by wrapping a L 35 m long wire around a hollow tube of diameter D 4.5 cm. The wire diameter is d 0.85 mm. The solenoid wire is then connected to a power supply so that a current of I 8.5 A flows through the Wire Randomized Variables 35 D 4.5 cm d 0.85 mm. Assignment Status 85 Click here for A 20% Part (a) Write an expression for the number of turns, N, in the solenoid. You do not need to take into account the diameter of the wire detailed view in this calculation. Grade Summary Deductions Time Remaining Potential 100% 0:59:27 Submissions d IAN 4 5 6 Attempts remaining 2 Problem Status 4% per attempt) detailed view m P t BACKSPACE CLEAR Feedback: El A 20% Part (b) Calculate the number of turns, N, in the solenoid. A 20% Part (c) Write an expression for the length of the solenoid (L n terms of the diameter of the hollow tube D, the length of the wire L by only 1 ayer of loops (note that most solenoids are actually constructed with and the diameter of the wire d Assume it is constructed using many layers, to maximize the magnetic field density) A 20% Part (d) Calculate the length of the solenoid (L2) in meters A 20% Part (e) Calculate the magnitude of the magnetic field at the center of the solenoid in tesla. C 2016 Expert TA, LLCExplanation / Answer
a) Circumference of hollow tube = pi*D
No. of turns = N = L/(pi*D)
b) No. of turns = N = L/(pi*D) = 35/(pi*0.045) = 247.6 turns
c) Length of the solenoid = L2 = No. of turns* diameter of wire
L2 = [L/(pi*D)]*d
d) L2 = [L/(pi*D)]*d = 247.6*0.85*10^-3 = 0.21 m = 21 cm
e) Magnetic field = B = uo*n*I = (4pi*10^-7*247.6*8.5/0.21) = 12.6 mT
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