Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose average

Question

Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose average formula is C_12H_26. (a) Determine the balanced equation, using the simplest whole-number coefficients, for the complete combustion of kerosene to gases. Include physical states of each reactant and product. (b) If DeltaH^0 = -1.50 times 10^4 kJ for the combustion equation as written in part (a), determine DeltaH^0_f of rxn kerosene. kJ/mol (c) Calculate the heat produced by the combustion of 0.74 gal of kerosene (d of kerosene = 0.749 g/mL). kJ (d) How many gallons of kerosene must be burned for a kerosene furnace to produce 1,158 Btu (1 Btu = 1.055 kJ)? gallons

Explanation / Answer

1) 2 CH3(CH2)10CH3 + 37 O2 => 24 CO2 + 26 H2O (H°f O2 = 0 , H°f CO2= -393.5 kj /mole

2) H°rxn = H°f (products) - H°f (reactants)   H°f H2O =-285.8  kj /mole)

- 150 * 104 = ( 24 * -393.5 + 26 *-285.8 - ( 2 Hf kerocene + 37 * 0)

- 150 * 104 = - 9444 - 7430 - 2Hf kerocene

2Hf kerocene = =-16874 + 1500000 = 1483.126 * 103 j/mol =1483.126 KJ/mol

Hf kerocene = 1483.126/2 = 741.56 KJ/mole

3) 1 gal = 3.79 lit

mass of kerocene = density * volume = 0.749* 0.74* 3.79 = 2.100g

moles of kerocene = 0.74 g / 170 = 0.00435 moles

heat produced = 0.00435 *  741.56= 3.22KJ /mole

4)

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