The answer choice is: a: g b: g/2 c: g/3 d: g/4 e:g/5 f g/6 g g/7 The second que
ID: 1451127 • Letter: T
Question
The answer choice is:
a: g
b: g/2
c: g/3
d: g/4
e:g/5
f g/6
g g/7
The second question is: neglecting the mass of the pulley what is the tension in the vertical part of the string after the system release from the rest?
a: mg
b: mg/3
c: mg/2
d: 2mg/3
e 3mg/4
f: 4mg/5
g: 5mg/6
h 6mg/7
Neglecting the mass of the pulley what is the tension in the horizontal part of the string after the system is rellease from the rest?
mg
mg/3
mg/2
2mg/3
3mg/4
4mg/5
5mg/6
6mg/7
Neglecting the mass of the pulley. after the ball has accelerated through some distance, how is the system's
kinetic energy split between the cart and the ball? The answer choice are:
the cart has 80% of the kinetic energy and the ball has 20%
the cart has 75% of the kinetic energy and the ball has 25%
the cart has 67% of the kinetic energy and the ball has 33%
the cart has 60% of the kinetic energy and the ball has 40%
the cart has half the kinetic energy and the ball has half the kinetic energy
the cart has 40% of the kinetic energy and the ball has 60%
the cart has 33% of the kinetic energy and the ball has 67%
the cart has 25% of the kinetic energy and the ball has 75%
the cart has 20% of the kinetic energy and the ball has 80%
Explanation / Answer
here,
(a)
the accelration , a = net force /effective mass
a = ( m * g)/( m + 4m + 0.5 * 2 * m * r^2 /r^2)
a = g/6
the accelration is f) a = g/6
(b)
neglecting the mass of the pulley ,
a = m * g /( 4m + m)
a = g/5
then ,
m * g - T = m * a
m*g - T = m * g/5
f. T = (4/5)*g
(C)
tension in the string is same
the tension is (4/5)g
(D)
the speed of both cart and ball is same
but their masses are different
mc : mb = 4:1
so
as KE directly proportional to mass
KEc : KEb = 4 : 1
therefore,
the cart has 80% of the kinetic energy and the ball has 20%
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