A 10.0-g projectile is fired at 100. m/s toward a stationary 10.00-kg target. Wh

Question

A 10.0-g projectile is fired at 100. m/s toward a stationary 10.00-kg target. When struck, the target breaks into two pieces with masses 9.80 kg and 0.20 kg. The original projectile and the smaller part of the target fly off along the original direction of the projectile at speeds of 60.0 m/s and 20.0 m/s, respectively. Calculate the velocity (including direction) of the larger piece of the target after the collision. (The results may be surprising, but they are quite real. See "A physicist examines the Kennedy assassination film," Luis W. Alvares, American Journal of Physics, 44(9), 813-827 (1976).)

Explanation / Answer

using law of conservation of momentum

along original direction

(10*10^-3*100)+0 = ((10*10^-3)*60)+(0.2*20) + (9.8*v)

v = -0.367 m/s

then speed of the larger velocity is 0.367 m/s opposite to the original direction

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