An advertisement shows a 1239 kg car slowly pulling at constant speed a large pa

Question

An advertisement shows a 1239 kg car slowly pulling at constant speed a large passenger airplane to demonstrate the power of its newly-designed 74.7-hp (horsepower) engine. During the pull, the car passed two landmarks spaced 25.0 meters apart in 11.3 seconds. The passenger plane being towed is a Boeing 707, with a total weight of 62.5 tons. Calculate the force that opposes the motion. Assume that the efficiency of the car is such that 20.9% of the engine power is available to propel the car forward. How much work is performed by the car on the airplane during this time? How much work is performed by the airplane on the car during this time?

Explanation / Answer

here,

mass of the car , m = 1239 kg

power of car , Pi = 74.7 hp

Pi = 55703.78 W

Po = e * pi = 0.209 * 55703.78 = 11642.09 W

s = 25 m

t = 11.3 s

work done , W = P * t = 11642.09 * 11.3

W = 1.32 * 10^5 J

the force that opposes the motion , F = W/d

F = 1.32 * 10^5 / 25

F = 5262.22 N

the force that opposes the motion is 5262.22 N

work done by the car on the airplane is 1.32 * 10^5 J in forward direction

work done by airplane on car is 1.32 * 10^5 J in opposite direction

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