I am having a problem with a couple of homework questions : A proton is moving p
ID: 1449091 • Letter: I
Question
I am having a problem with a couple of homework questions :
A proton is moving perpendicular to a magnetic field at 5.0 ´ 106 m/s and experiences a magnetic force of magnitude 4.5 ´ 10-16 N. What is the magnitude of the magnetic field?
An electron is moving at 3.5 ´ 106 m/s perpendicular to a 3.5 mT magnetic field. What is the radius of its path?
A mass spectrometer splits a beam of 10B and 11B singly charged ions having the same velocity by passing the beam through a uniform magnetic field. If the radius of the path for the 10B ions is 14.0 cm, what will be the radius for the 11B ions?
A singly charged 9Be ion is accelerated from rest through a potential difference of 9000 V. The ion is then sent into a mass spectrometer where the radius of the path is 25 cm. What is the magnetic field in the spectrometer?
Find the force (magnitude and direction) exerted on an electron moving vertically upward( gravitationally) at a speed of 2.0 ´ 107 m/s by a horizontal magnetic field of 0.40 T directed north.
An electron is moving at 3.0 ´ 106 m/s at an angle of 35° to a 0.80 T magnetic field. What is the magnitude of the acceleration of the electron?
The magnetic field in a cyclotron is 0.70 T. What is the radius of the vacuum chamber for a maximum proton velocity of 1.0 ´ 107 m/s? ( the proton must make a full circle)
A velocity selector for ions uses perpendicular electric and magnetic fields. If the electric field used were 900 V/m, what magnetic field would allow the selection of a velocity of 4000 m/s?
A long straight wire is carrying a current of 2.6 A in a region where the magnetic field is perpendicular to the wire. If the magnetic field is 0.58 mT, what is the magnitude of the force on 2.5 m of the wire?
A 400 turn coil of area 25 cm2 is placed in an 90 mT magnetic field. If the coil carries a current of 4.3 A, what is the magnitude of the maximum magnetic torque it could experience?
A power line carries 1000 A at a height of 15 m above the ground. What is the resulting magnetic field at ground level?
Two parallel wires run in a north-south direction. The eastern wire carries 15.0 A southward while the western wire carries 6.0 A northward. If the wires are separated by 30 cm, what is the magnetic field strength and direction at a point between the wires at a distance of 10 cm from the western wire?
What current is necessary to generate a field of 0.20 T inside a circular loop of 50 turns and radius 15.0 cm?
A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 m T magnetic field is perpendicular to both the rod and its velocity. What is the potential difference between the ends of the rod?
A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 m T magnetic field is perpendicular to both the rod and its velocity. What is the magnetic flux swept through per second by the rod?
A conducting rod slides at 3.0 m/s on metal rails separated by 2.0 m. The 0.66 mT magnetic field is into the paper. If the resistance is 220 mW, what is the current in the circuit?
The emf produced by an ac generator is given by e = wNBA sin wt. In the SI system, what is the value of w for a frequency of 60.0 Hz?
For the typical "European household ac voltage" of 240 V", what is the amplitude of the emf?
A generator has 400 turns of wire on a coil of radius 2.00 cm. What rotational speed is necessary to produce an emf of amplitude 4.50 V if the magnetic field in the region of the coil is 0.180 T?
20. A flat coil has a maximum flux 5.0 ´ 10-3 T·m2 through it as its area is perpendicular to a uniform magnetic field. When the coil is rotated 60° (so that its normal makes a 60° angle with the field), what is the flux through it?
Explanation / Answer
1) magnetic field = (4.5 * 10-16 )/(1.6 * 10-19 * 5.0 * 106)
= 5.625 * 10-4 T
2) radius = ( 9.11 * 10-31 * 3.5 * 106)/(1.6 * 10-19 * 3.5 * 10-3)
= 5.69 mm
3) radius for the 11B ions = (11/10) * 14
= 15.4 cm
4) velocity of ion = sqrt(2 * 1.6 * 10-19 * 9000 * 6.023 * 1023/0.009)
= 4.39 * 105 m/sec
=> magnetic field = (0.009/ 6.023 * 1023) * 4.39 * 105/(1.6 * 10-19 * 0.25)
= 0.164 T
5) Force = 1.6 * 10-19 * 2 * 107 * 0.40
= 1.28 * 10-12 N (towards east)
6) acceleration = (1.6 * 10-19 * 3 * 106 * 0.80 * sin35)/(9.11 * 10-31)
= 2.417 * 1017 m/sec2
7) radius = (1.67 * 10-27 * 107)/(1.6 * 10-19 * 0.70)
= 0.149 m
8) magnetic field = 900/4000
= 0.225 T
9) Force = 2.5 * 2.6 * 0.58 * 10-3
= 3.77 mN
10) torque = 400 * 4.3 * 25 * 10-4 * 90 * 10-3
= 0.387 N.m
11) magnetic field = 2 * 10-7 * 1000/15
= 1.33 * 10-5 T
12) magnetic field = 2 * 10-7 * (6/0.1 - 15/0.2)
= 3 * 10-6 T
Direction = inward plane of paper
13) current = ( 2 * 0.15 * 0.20)/(4 * 3.14 * 10-7 * 50)
= 955.41 A
14) potential difference = 2 * 6 * 5 * 10-3
= 0.06 V
15) magnetic flux swept through per second = 0.06 Wb/sec
16) current = (3 * 2 * 0.66 * 10-3)/0.22
= 0.018 A
17) w = 2 * 3.14 * 60
= 376.8 rad/sec
18) amplitude = 240 * 1.414 = 339.36 V
19) rotational speed = (4.50)/(400 * 0.180 *3.14 * 0.02 * 0.02)
= 49.76 rad/sec
20) flux through it = 5 * 10-3 * cos60
= 2.5 * 10-3 T.m2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.