1. The equivalent resistance connected across the (9.00 V) seat of EMF equals 2.
ID: 1448493 • Letter: 1
Question
1. The equivalent resistance connected across the (9.00 V) seat of EMF equals
2. Resistor R4 carries a current of
3. The potential difference between points “c” and “d” equals
4. Resistor R1 carries a current of
5. Resistor R3 carries a current of
6. The potential difference across the battery’s terminals from point “a” to point “b” equals
7. The power dissipated in the internal resistance of the battery is
Please show ALL work! Thank you.
The circuit shown below contains four resistors and one real battery having an EMF of 9.00 V and an internal resistance "r"-1.00 . R4 (600 ) R1 (400 ) T9.00 V R3 (3.00 ) R2 (2.00 ) (1 00 )Explanation / Answer
R1 , R2 are in series
R12 = 4 +2 = 6 ohms
R12 . R3 are in parallel
R123 = (R12*R3)/(R12+R3) = (6*3)/(6+3) = 2 ohms
R123 , R4 , r are in series
Req = R123 + R4 +r = 2 + 6 + 1 = 9 ohms <<<-----answer
+++++
2)
I4 = E/Req = 9/9 = 1 A
_________
3)
Vcd = E - I4*(R4+r) = 9 - 1*(6+1) = 9- = 2V
+++++++++++
4)
I1 = Vcd/R12 = 2/6 = 1/3 A = 0.33 A
_________
5)
I3 = Vcd/R3 = 2/3 = 0.67 A
++++++
6)
vab = E - I4*r = 9-(1*1) = 8 V
_______
7)
P = I4^2*r = 1^2*1 = 1 W
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