Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question 5 0 out of 10 points When the voltage drop across a capacitor increases

ID: 1447641 • Letter: Q

Question

Question 5 0 out of 10 points When the voltage drop across a capacitor increases from 10.0 V to 15.0 V by what factor does the charge stored on the capacitor increase? Question 6 10 out of 10 points While charging with a 20.0 V power supply, you measure the voltage across the capacitor as 12.0 What is the voltage across the resistor? Question 7 0 out of 5 points When discharging the 20.0 mF capacitor, you measure a voltage of 11.2 V across the capacitor. What is the voltage drop across the 300.0 resistor?

Explanation / Answer

5)

C = Capacitance

Q1 = initial charge                    , V1 = initial voltage = 10 volts

Q2 = final charge                    , V2 = final voltage = 15 volts

Charge stored is given as , Q = CV

hence , Q1/Q2 = V1/V2

Q1/Q2 = 10/15

Q2 = 1.5 Q1

hence charge becomes 1.5 times

6,

battery voltage = Voltage in capacitor + Voltage in resistor

20 = 12 + Voltage in resistor

Voltage in resistor = 8 volts

7.

11.2 volts .

same as the Voltage in capacitor, since resistor is in parallel with capacitor

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote