Apply Newton’s second law for charged pith ball in equilibrium position. Solve f

Question

Apply Newton’s second law for charged pith ball in equilibrium position. Solve for the electrostatic force and using the value of the charge on the pith ball calculate the maximum value Emax of the electric field between parallel plates assuming that the field is uniform. Clearly show your calculations using the proper variable terminology. Define any variables that you create (e.g.,Fe-electrostatic forceon pith ball).

Thus far I have solved Ft=4.9 x 10^-4; Fe = 3.28 x 10^-4, I am having difficulty figuring out what they are asking and what formula to use to solve for it. Thank you for your help.

Explanation / Answer

let Electrostatic force is Fe

then Fe = q*Emax

then Emax = Fe/q = Fe/6.168*10^-9 = 1.62*10^8*Fe N/C

here Fe is the variable under consideration

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