(a) immediately after the switch is closed (after being open a long time)... ...

Question

(a) immediately after the switch is closed (after being open a long time)...
...the current through the inductor

IL =

...the current through R2

I2 =

(b) a long time after the switch has been closed...
...the current through the inductor
IL =

...the current through R2
I2 =

(c) immediately after the switch is open (after being closed a long time)...
...the current through the inductor
IL =

...the current through R2
I2 =

(d) a time 5.657e-04 s after the switch is open....
...the current through the inductor
IL =

...the current through R2
I2 =

Explanation / Answer

a) immediately after the switch is closed

IL = 0

b) a long time after the switch has been closed...

IL = E/R1 = 10/290 = 0.0344 Ampere

I2 = 0.0344ampere

c)   immediately after the switch is open (after being closed a long time

IL = 0.0344 ampere

d) current at time t is given by

I(t) = 0.0344*e-1.59t

hence at time t =  5.657e-04

I = 0.0291 ampere

IL =I2 = 0.0291 ampere

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