(a) immediately after the switch is closed (after being open a long time)... ...
ID: 1445764 • Letter: #
Question
(a) immediately after the switch is closed (after being open a long time)...
...the current through the inductor
IL = _________ mA
...the current through R2
I2 = _________mA
(b) a long time after the switch has been closed...
...the current through the inductor
IL = _________ mA
...the current through R2
I2 = _________mA
(c) immediately after the switch is open (after being closed a long time)...
...the current through the inductor
IL = __________mA
...the current through R2
I2 = __________mA
(d) a time 1.144e-03 s after the switch is open....
...the current through the inductor
IL = __________mA
...the current through R2
I2 = __________mA
Explanation / Answer
a) Just after switch is closed.
current doesn't change in indcutor instantly.
hence current through inductor = 0
IL = 0
current through R2, I2 = 10 / (210 + 300) = 0.0196 A = 19.6 mA
b) after long time.
no current will flow through R2, all the current will go through inductor.
iL = V/R1 = 10 / 210 = 0.0476 A = 47.6 mA
I2 = 0
c) current will not change instantly through inductor.
so IL = 47.6 mA
I2 = 47.6 mA
d) as time elapses, current through inductor start decreasing.
IL = I [ e^(-tR2/L) ]
at t = 1.144 x 10^-3 s
IL = 47.6 [ e^(- 1.144 x 10^-3 x 300 / 0.264)] = 12.97 mA
I2 = 12.97 mA
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