The process in a television tube can be simplified as the acceleration of electr
ID: 1446729 • Letter: T
Question
The process in a television tube can be simplified as the acceleration of electrons between two parallel, oppositely charged plates. You can use m_e for the electron's mass; e for its charge, d for the distance between the plates; g for gravitational acceleration and any other tabulated data from the charts, if needed. For an electron, released from the negative plate, what is its acceleration due to Coulomb interactions as it reaches the screen (i.e., the positive plate)? Assume voltage difference V_0 between the plates. If one is to rotate the TV so that the screen is looking upwards, how much voltage V should be applied to counter the electric force with the gravitational force over a distance of d between the plates, so that the electron stays where it is, without neither going up or down?Explanation / Answer
1) initial velocity =0
Force=eE=ma
acceleration=eE/m
E=V.d
acceleration=eV0d/m
2) Fgravitational=mg
Felectric=qE=qV/d
Remain stays where it is then
qV/d=mg
V=mgd/q
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