A stone used to grind wheat into flour is turned through 12 revolutions by a con

Question

A stone used to grind wheat into flour is turned through 12 revolutions by a constant force of 21.8 N applied to the rim of a 9.6-cm-radius shaft connected to the wheel. How much work is done on the stone during the 12 revolutions? The radius of a wheel IS 0.550 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 4.59 N, unwinding the rope and making the wheel spin CCW about its central axis. Ignore the mass of the rope. How much rope unwinds while the wheel makes 1.00 revolution? How much work is done by the rope on the wheel during this time?

Explanation / Answer

Here,

theta = 12 revs

force , F = 21.8 N.m

radius ,r = 9.6 cm = 0.096 m

work done on the stone = F * theta

work done on the stone = 21.8 * 21 * 2pi

work done on the stone = 21.8 * 21 * 6.282

work done on the stone = 2875.9 J

the work done on the stone is 2875.9 J

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